-5b^2=3b

Solution for -5b^2=3b equation:

-5b^2=3b

We move all terms to the left:

-5b^2-(3b)=0

a = -5; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·(-5)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*-5}=\frac{0}{-10}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*-5}=\frac{6}{-10}
=-3/5
$